jackson23sun 發表于 2015-9-8 17:35
ln(1+e^x)-ln(1+e^(-x))=ln[(1+e^x)/(1+e^(-x))]=lne^x=x
Edwin- 發表于 2015-9-8 17:47
我沒算出來等于e^x那步
jackson23sun 發表于 2015-9-8 18:14
。。。把分子提出個e^x就好了啊,
1+e^x=e^x(1+e^(-x))
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